Optimal. Leaf size=214 \[ -\frac{\left (15 a e^2 g^2+c \left (-d^2 g^2+8 d e f g+8 e^2 f^2\right )\right ) \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )}{4 e^{3/2} (e f-d g)^{7/2}}-\frac{\sqrt{f+g x} \left (a e^2+c d^2\right )}{2 e (d+e x)^2 (e f-d g)^2}+\frac{\sqrt{f+g x} \left (7 a e^2 g+c d (8 e f-d g)\right )}{4 e (d+e x) (e f-d g)^3}+\frac{2 \left (a g^2+c f^2\right )}{\sqrt{f+g x} (e f-d g)^3} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.504543, antiderivative size = 214, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.208, Rules used = {898, 1259, 456, 453, 208} \[ -\frac{\left (15 a e^2 g^2+c \left (-d^2 g^2+8 d e f g+8 e^2 f^2\right )\right ) \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )}{4 e^{3/2} (e f-d g)^{7/2}}-\frac{\sqrt{f+g x} \left (a e^2+c d^2\right )}{2 e (d+e x)^2 (e f-d g)^2}+\frac{\sqrt{f+g x} \left (7 a e^2 g+c d (8 e f-d g)\right )}{4 e (d+e x) (e f-d g)^3}+\frac{2 \left (a g^2+c f^2\right )}{\sqrt{f+g x} (e f-d g)^3} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 898
Rule 1259
Rule 456
Rule 453
Rule 208
Rubi steps
\begin{align*} \int \frac{a+c x^2}{(d+e x)^3 (f+g x)^{3/2}} \, dx &=\frac{2 \operatorname{Subst}\left (\int \frac{\frac{c f^2+a g^2}{g^2}-\frac{2 c f x^2}{g^2}+\frac{c x^4}{g^2}}{x^2 \left (\frac{-e f+d g}{g}+\frac{e x^2}{g}\right )^3} \, dx,x,\sqrt{f+g x}\right )}{g}\\ &=-\frac{\left (c d^2+a e^2\right ) \sqrt{f+g x}}{2 e (e f-d g)^2 (d+e x)^2}-\frac{g^3 \operatorname{Subst}\left (\int \frac{\frac{4 e^2 (e f-d g) \left (c f^2+a g^2\right )}{g^5}+\frac{e \left (3 a e^2 g^2-c \left (4 e^2 f^2-8 d e f g+d^2 g^2\right )\right ) x^2}{g^5}}{x^2 \left (\frac{-e f+d g}{g}+\frac{e x^2}{g}\right )^2} \, dx,x,\sqrt{f+g x}\right )}{2 e^2 (e f-d g)^2}\\ &=-\frac{\left (c d^2+a e^2\right ) \sqrt{f+g x}}{2 e (e f-d g)^2 (d+e x)^2}+\frac{\left (7 a e^2 g+c d (8 e f-d g)\right ) \sqrt{f+g x}}{4 e (e f-d g)^3 (d+e x)}+\frac{g^3 \operatorname{Subst}\left (\int \frac{\frac{8 e^2 \left (c f^2+a g^2\right )}{g^4}+\frac{e \left (7 a e^2 g+c d (8 e f-d g)\right ) x^2}{g^3 (e f-d g)}}{x^2 \left (\frac{-e f+d g}{g}+\frac{e x^2}{g}\right )} \, dx,x,\sqrt{f+g x}\right )}{4 e^2 (e f-d g)^2}\\ &=\frac{2 \left (c f^2+a g^2\right )}{(e f-d g)^3 \sqrt{f+g x}}-\frac{\left (c d^2+a e^2\right ) \sqrt{f+g x}}{2 e (e f-d g)^2 (d+e x)^2}+\frac{\left (7 a e^2 g+c d (8 e f-d g)\right ) \sqrt{f+g x}}{4 e (e f-d g)^3 (d+e x)}+\frac{\left (15 a e^2 g^2+c \left (8 e^2 f^2+8 d e f g-d^2 g^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{-e f+d g}{g}+\frac{e x^2}{g}} \, dx,x,\sqrt{f+g x}\right )}{4 e g (e f-d g)^3}\\ &=\frac{2 \left (c f^2+a g^2\right )}{(e f-d g)^3 \sqrt{f+g x}}-\frac{\left (c d^2+a e^2\right ) \sqrt{f+g x}}{2 e (e f-d g)^2 (d+e x)^2}+\frac{\left (7 a e^2 g+c d (8 e f-d g)\right ) \sqrt{f+g x}}{4 e (e f-d g)^3 (d+e x)}-\frac{\left (15 a e^2 g^2+c \left (8 e^2 f^2+8 d e f g-d^2 g^2\right )\right ) \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )}{4 e^{3/2} (e f-d g)^{7/2}}\\ \end{align*}
Mathematica [C] time = 0.107233, size = 140, normalized size = 0.65 \[ \frac{2 \left (g \left (g \left (a e^2+c d^2\right ) \, _2F_1\left (-\frac{1}{2},3;\frac{1}{2};\frac{e (f+g x)}{e f-d g}\right )+2 c d (e f-d g) \, _2F_1\left (-\frac{1}{2},2;\frac{1}{2};\frac{e (f+g x)}{e f-d g}\right )\right )+c (e f-d g)^2 \, _2F_1\left (-\frac{1}{2},1;\frac{1}{2};\frac{e (f+g x)}{e f-d g}\right )\right )}{e^2 \sqrt{f+g x} (e f-d g)^3} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [B] time = 0.224, size = 546, normalized size = 2.6 \begin{align*} -2\,{\frac{a{g}^{2}}{ \left ( dg-ef \right ) ^{3}\sqrt{gx+f}}}-2\,{\frac{c{f}^{2}}{ \left ( dg-ef \right ) ^{3}\sqrt{gx+f}}}-{\frac{7\,a{e}^{2}{g}^{2}}{4\, \left ( dg-ef \right ) ^{3} \left ( egx+dg \right ) ^{2}} \left ( gx+f \right ) ^{{\frac{3}{2}}}}+{\frac{c{d}^{2}{g}^{2}}{4\, \left ( dg-ef \right ) ^{3} \left ( egx+dg \right ) ^{2}} \left ( gx+f \right ) ^{{\frac{3}{2}}}}-2\,{\frac{ \left ( gx+f \right ) ^{3/2}cdefg}{ \left ( dg-ef \right ) ^{3} \left ( egx+dg \right ) ^{2}}}-{\frac{9\,{g}^{3}ead}{4\, \left ( dg-ef \right ) ^{3} \left ( egx+dg \right ) ^{2}}\sqrt{gx+f}}+{\frac{9\,a{e}^{2}{g}^{2}f}{4\, \left ( dg-ef \right ) ^{3} \left ( egx+dg \right ) ^{2}}\sqrt{gx+f}}-{\frac{c{d}^{3}{g}^{3}}{4\, \left ( dg-ef \right ) ^{3} \left ( egx+dg \right ) ^{2}e}\sqrt{gx+f}}-{\frac{7\,c{d}^{2}{g}^{2}f}{4\, \left ( dg-ef \right ) ^{3} \left ( egx+dg \right ) ^{2}}\sqrt{gx+f}}+2\,{\frac{eg\sqrt{gx+f}cd{f}^{2}}{ \left ( dg-ef \right ) ^{3} \left ( egx+dg \right ) ^{2}}}-{\frac{15\,ae{g}^{2}}{4\, \left ( dg-ef \right ) ^{3}}\arctan \left ({e\sqrt{gx+f}{\frac{1}{\sqrt{ \left ( dg-ef \right ) e}}}} \right ){\frac{1}{\sqrt{ \left ( dg-ef \right ) e}}}}+{\frac{c{d}^{2}{g}^{2}}{4\, \left ( dg-ef \right ) ^{3}e}\arctan \left ({e\sqrt{gx+f}{\frac{1}{\sqrt{ \left ( dg-ef \right ) e}}}} \right ){\frac{1}{\sqrt{ \left ( dg-ef \right ) e}}}}-2\,{\frac{cdfg}{ \left ( dg-ef \right ) ^{3}\sqrt{ \left ( dg-ef \right ) e}}\arctan \left ({\frac{e\sqrt{gx+f}}{\sqrt{ \left ( dg-ef \right ) e}}} \right ) }-2\,{\frac{ce{f}^{2}}{ \left ( dg-ef \right ) ^{3}\sqrt{ \left ( dg-ef \right ) e}}\arctan \left ({\frac{e\sqrt{gx+f}}{\sqrt{ \left ( dg-ef \right ) e}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [B] time = 2.14663, size = 3135, normalized size = 14.65 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [A] time = 1.18016, size = 487, normalized size = 2.28 \begin{align*} \frac{{\left (c d^{2} g^{2} - 8 \, c d f g e - 8 \, c f^{2} e^{2} - 15 \, a g^{2} e^{2}\right )} \arctan \left (\frac{\sqrt{g x + f} e}{\sqrt{d g e - f e^{2}}}\right )}{4 \,{\left (d^{3} g^{3} e - 3 \, d^{2} f g^{2} e^{2} + 3 \, d f^{2} g e^{3} - f^{3} e^{4}\right )} \sqrt{d g e - f e^{2}}} - \frac{2 \,{\left (c f^{2} + a g^{2}\right )}}{{\left (d^{3} g^{3} - 3 \, d^{2} f g^{2} e + 3 \, d f^{2} g e^{2} - f^{3} e^{3}\right )} \sqrt{g x + f}} - \frac{\sqrt{g x + f} c d^{3} g^{3} -{\left (g x + f\right )}^{\frac{3}{2}} c d^{2} g^{2} e + 7 \, \sqrt{g x + f} c d^{2} f g^{2} e + 8 \,{\left (g x + f\right )}^{\frac{3}{2}} c d f g e^{2} - 8 \, \sqrt{g x + f} c d f^{2} g e^{2} + 9 \, \sqrt{g x + f} a d g^{3} e^{2} + 7 \,{\left (g x + f\right )}^{\frac{3}{2}} a g^{2} e^{3} - 9 \, \sqrt{g x + f} a f g^{2} e^{3}}{4 \,{\left (d^{3} g^{3} e - 3 \, d^{2} f g^{2} e^{2} + 3 \, d f^{2} g e^{3} - f^{3} e^{4}\right )}{\left (d g +{\left (g x + f\right )} e - f e\right )}^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]